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Dark Matter


So how do we weigh the universe?

Can only see luminous matter: how much Dark Matter is there? Usually expressed as mass to luminosity ratio (Upsilon) Υ = M/L; For sun

Υ₀ = M₀/L₀ ≈ 5000 kg/W

First Guess: What you see is what you get!


1st order estimate:


Masses of Spiral galaxies

direct observation i.e. measurement of velocities of individual stars in nearby => rotation curves or measurement of hydrogen via 21cm line or estimates of no. of stars
Luminosity of galaxy should reflect mass

Typical Spiral (NGC3198) R ≈ 20 kpc but outer parts are just seen as H gas

Should be able to calculate rotational speed

In core of galaxy,

 mv²/r1  = G M(r1)m/r1²
M(r1) is mass inside orbit: total mass
M =⁴/3 πR³ ρ
and
M(r1) = ⁴/3 π r1³ ρ = M r1³/R³
Hence inside core:
v²/r  = G Mr³/(r²R³) or v = (GMr²/R³)1/2

Outside core:

mv²/r  = GMm/r² or v = (GM/r)1/2

Most of the light is fairly concentrated, so this should be good approx to the mass.
These show rotation curves

i.e. velocity curve doesn't drop as expected

Can fix this by saying that galaxy has halo of dark matter around it. Hence outside core but still inside halo force = force due to core + force due to halo
v²/r  =  GM/r²   +   G M'r³/(r²R'³) 
or
v = (GM/r + GM'r²/R'³)1/2

Not perfect: by fitting we can get a better result

Halo + core add together to give correct curve


For spirals
\color{red}{ \frac{{10M_o }}{{L_o }} < \frac{M}{L} < \frac{{40M_o }}{{L_o }}}

Implication: Mass of observed galaxy ≈ 1010 M₀, R ≈ 2 kpc (for core)
Mass of halo ≈ 1013M₀, R ≈ 100kpc (except that we can't measure out there!)

Note average density in halo ∼ 10-21 ∼ 106 x critical density

What do we mean by mass of galaxy? In fact the visible part of the galaxy may just reflect the dark matter.


Large clusters of galaxies:

By measuring vel. cpt. in line of sight (via Doppler) can get estimate of M from virial theorem
<K.E.> = -1/2<P.E.> 
for a cluster, this becomes
Hence
\color{red}{ M = \frac{{r_h \left\langle {v^2 } \right\rangle }}{{\alpha G}}}
Radial vel. of individual galaxies given by
\color{red}{ \left\langle {v^2 } \right\rangle = \left\langle {\left( {v_r - \left\langle {v_r } \right\rangle } \right)^2 } \right\rangle \sim 2x10^{12} }
Roughly for Coma, rh ∼ 1.5 Mpc, so
\color{red}{ M_{Coma} \approx 10^{15} M_ \odot ,L_{Coma} \approx 10^{13} L_ \odot }

This gives much higher masses than indivdual spirals

\color{red}{ \frac{M}{L} \approx \frac{{250M_o }}{{L_o }}}

A check: Large clusters contain a lot of hot gas, which is strong X-ray source

X-ray pictures measure density and temp:


Can use Hydrostatic Equilibrium equation and Eqn. of State to estimate mass (just as we did with stellar modelling
Also large clusters show gravitational lensing, can get quantitative estimate: Einstein ring (if lensing is perfect)
\color{red}{ \theta _E = \left( {\frac{{4GM}}{{c^2 d}}\frac{{1 - x}}{x}} \right)}
if distance is d and lensing object is at xd

The Bullet Cluster
Note that the larger the object, the more massive (proportionately) that it is.