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Inflation

Theseo 2000

`I can't believe THAT!' said Alice.

`Can't you?' the Queen said in a pitying tone. `Try again: draw a long breath, and shut your eyes.'

Alice laughed. `There's not use trying,' she said: `one CAN'T believe impossible things.'

`I daresay you haven't had much practice,' said the Queen. `When I was your age, I always did it for half-an-hour a day. Why, sometimes I've believed as many as six impossible things before breakfast. '


Inflation

We are left with two major problems: the flatness problem and the horizon problem, and also one you haven't head of: the monopole problem

Why the Hell?

At any time, critical energy density is given by
\color{red}{ \varepsilon _c \left( t \right) = \frac{{3c^2 H^2 }}{{8\pi G}}}
so (YAWOWTFE)
\color{red}{ H\left( t \right)^2 = H\left( t \right)^2 \Omega - \frac{{\kappa c^2 }}{{R_0^2 a\left( t \right)^2 }}}
which can be rewritten
\color{red}{ H_0^2 \left( {\Omega _0 - 1} \right) = H\left( t \right)^2 a\left( t \right)^2 \left( {\Omega \left( t \right) - 1} \right)}
so (1-Ω) can never change sign.
Suppose (for simplicity) we have a radiation-dom. universe (doesn't affect the argument)
\color{red}{ \Omega \left( t \right) = 1 + \left( {1 - \frac{1}{{\Omega _0 }}} \right)a^2 }
  • If κ = 0, Ω = 1 for all time
  • If κ > 0, then Ω decreases away from 1.
  • Ifκ < 0, then Ω increases away from 1.
This is the "flatness problem"

Since we measure Ω now ≈ .1...this means that at the time of the BB, Ω ≈ 1 - 10-60

i.e. Ω = 1 is an unstable critical point

The flatness problem is worse than you would think: If the universe started out at 10-44 s with (say) Ω = 3, it would last ≈ 10-35 s (!!!!)

Horizon problem:

Parts of the universe separated by Hubble dist. d > c/H
More exactly: the most distant object that we can see today is given by the "horizon distance":
in general, this is
\color{red}{ d_{hor} \left( t \right) = ca\left( {t_0 } \right)\int_0^{t_o } {\frac{{dt}}{{a\left( t \right)}}} \Rightarrow c\int_0^{t_o } {\frac{{dt}}{{a\left( t \right)}}} }

(note light is emitted at t = 0). If we have a one-component universe, this is
\color{red}{ \frac{{a\left( {t_0 } \right)}}{{a\left( t \right)}} = \left( {\frac{{t_0 }}{e}} \right)^{2/\left( {3 + 3w} \right)} w \ne - 1}
so
\color{red}{ d_{hor} \left( {t_0 } \right) = \frac{c}{{H_0 }}\frac{2}{{1 + 3w}}}
so in matter-dom universe (w=0), this is now
\color{red}{ d_{hor} = \frac{{2c}}{{H_0 }} \approx 2.6 \times 10^{26} m}
Note if w <-1/3, dhor=∞: i.e. can see all the universe.

Space-time defects

Many systems in physics show "spontaneously broken symmetry"
e.g. a ferromagnet is made up of electron spins which can point
  • at high temp, in any direction
  • at low temp, all in the same direction, but that direction is arbitrary

What actually happens is a bit more complicated: if you take a slab of Fe and cool it, different parts will choose different directions. These are domains: you can make them all the same by (e.g.) hitting the magnet in a mag field.

Theories of matter work in a somewhat similar way: can have (e.g.) the electromagnetic coupling chosen differently in different parts of space via a phase factor: (q = q0e ). This can't be seen as long as θ varies smoothly from one point in space to another (local gauge invariance)
Hierarchy of theories: simplest at highest temps:

At very high energy, symmetry is unbroken: at lower energy universe must choose between different vacua.
In particular, Higgs field (gives rise to mass of particles) becomes spontaneously broken since minimum has a random phase

However since the universe starts off very hot, these are arranged randomly. When the universe cools, bits of space can be trapped with different values.

There are three possible structures:
  • Domain walls vanish (noisily!)
  • Monopoles behave like extremely massive particles (and hence could be related to dark matter).
  • Cosmic strings are the most interesting, since they behave like infinitely thin, long loops of string with a mass of 1020 kg/m. Analogous to vortices in a fluid

How would we see them?

The inflationary universe

solves these problems:
consider a very small volume of the (original) universe.

e.g. at t = 10-34 s, the size of the horizon is d = ct = 10-23 cm (≈ 10-8 size of a proton)

The inflationary phase leads to an increase in the size of universe by 1080 (effect is very like continuous creation, in that the energy density remains the same).

(diagram not exactly to scale!)

An inflationary phase "smoothes out the wrinkles". The temperature in this volume was already in equilibrium. Now, after inflation, it is much larger and smoother than before.

How do we get this? This was one "special case": if vacuum itself has an energy ρv=Λ/3 ≠0? Obviously $$ \color{red}{ \frac{{d\rho _v }}{{dt}} = 0} $$

so (setting ρm= ρr=0 for simplicity) we can use $$ \color{red}{ \left( {\frac{{\dot a}}{a}} \right)^2 = \frac{\Lambda }{3}} $$

which is our previous results with w = -1: this gives$$ \color{red}{ a(t) = a_0 e^{\sqrt {\frac{\Lambda }{3}} t} } $$ Note that

\color{red}{ H_i = \frac{{\dot a}}{a} = \sqrt {\frac{{\Lambda _i }}{3}} }
i.e. Hubble param is constant.
Assume that inflation switches on at ti and off at tf. Then scale param at start of inflation is ai so before
\color{red}{ a\left( t \right) = a_i \left( {\frac{t}{{t_i }}} \right)^{1/2} }
so
\color{red}{ H_i = \frac{{\dot a}}{a} = \frac{1}{{2t_i }} \approx 10^{36} s^{ - 1} }
(which obviously fixes Λ)
Usual to talk about E-foldings:
\color{red}{ N = \frac{{t_f - t_i }}{{H_i }}}
Number of times that universe expanded by a factor of e.

Flatness problem

At 10-36 s, the universe could have deviated from Ω = 1.

\color{red}{ \Omega \left( t \right) - 1 = \frac{{\Omega _i - 1}}{{a\left( t \right)^2 }}}

After inflation, the density hasn't changed (remember steady state model?) but the universe is 1043 times larger!

This means that it can never deviate much from Ω = 1: i.e. flatness problem is fixed.


Horizon problem

\color{red}{ d_{hor} \left( t \right) = ca\left( {t_0 } \right)\int_0^{t_o } {\frac{{dt}}{{a\left( t \right)}}} \Rightarrow c\int_0^{t_o } {\frac{{dt}}{{a\left( t \right)}}} }
Before inflation,
\color{red}{ d_{hor} = \frac{{2c}}{H} = 2ct_i \sim 10^{ - 29} m}
(seriously: about 10-14x size of proton!) after inflation
\color{red}{ d_{hor} \left( {t_f } \right) = e^N c\left( {2t_i + \frac{1}{{H_i }}} \right) \sim 3ct_i e^N \sim 1 pc}

What we really want to do is to ensure that the currently visible universe was small enough prior to inflation that it could be in thermal contact. Surface of last scattering is at zls ≈1100 so proper distance
\color{red}{ \begin{array}{l} d_p \left( {t_0 } \right) = c\int_{t_e }^{t_o } {\frac{{dt}}{{a\left( t \right)}}} = c\int_{t_e }^{t_o } {\frac{{dt}}{{\left( {\frac{t}{{t_0 }}} \right)^{2/3} }}} = \frac{{3c}}{{t_0 }}\left( {1 - \left( {\frac{{t_e }}{{t_0 }}} \right)^{1/3} } \right) \\ = \frac{{2c}}{{H_0 }}\left( {1 - \frac{1}{{\sqrt {1 + z} }}} \right) \approx 4 \times 10^{26} m = 1.4 \times 10^4 Mpc \\ \end{array}}
(universe is matter-dom since then, so we know \color{red}{a\left( t \right) = \left( {\frac{t}{{t_0 }}} \right)^{2/3} }
After inflation ended,
\color{red}{ d_p \left( {t_f } \right) = a_f d_p \left( {t_0 } \right) \approx 1m}
Before inflation started,
\color{red}{ d_p \left( {t_i } \right) = e^{ - N} d_p \left( {t_f } \right) \approx 10^{ - 44} m}
which is much smaller than horizon

Monopole problem

Effectively, monopoles become so dilute at most one in our observable universe (but Cabrera saw it!)

Origins of Inflation: preamble

Need a scalar field (inflaton) with large energy density:
Pressure
\color{red}{ P = - \left( {\frac{{\partial U}}{{\partial v}}} \right)_S }
(v is volume: normally energy decreases as gas expands, here it increases) so
\color{red}{ P_\phi = \frac{1}{2}\frac{1}{{\hbar c^3 }}\left( {\dot \phi } \right)^2 - V\left( \phi \right)}
which gives us inflation if \color{red}{{\dot \phi }} is small. Fluid equation for inflaton is
\color{red}{ \dot \varepsilon _\varphi + 3\frac{{\dot a}}{a}\left( {\varepsilon _\varphi + P_\phi } \right) = 0}
which becomes (note \color{red}{\frac{{\partial V\left( \phi \right)}}{{\partial t}} = \dot \phi \frac{{\partial V}}{{\partial \phi }}} )
\color{red}{ \ddot \phi + 3H\left( t \right)\dot \phi = - \hbar c^3 \frac{{\partial V}}{{\partial \phi }}}
which looks like a equation of motion with some friction:
If \color{red}{{\dot \phi }} is small, can ignore \color{red}{{\ddot \phi }} . Hence can find \color{red}{{\dot \phi }} \color{red}{{\dot \phi }}
  • Start off in "false vacuum" at φ ≈ 0
  • \color{red}{{\dot \phi }} is small
  • so field "rolls" towards minimum
Would be nice and economical to do this with the Higgs field, but it changes too fast
\color{red}{ V = a\left| \phi \right|^4 - b\left| \phi \right|^2 + V_0 }

so scenario is
as the universe expands, the value of Ωφis static, but the other two fall. If we start off with any values of ΩM and ΩR but Ωφ=1, the other two will disappear during inflation

  • Start with radiation dominated universe ΩR >> Ωφ >> ΩM, φ ≈ 0
  • Cool until ΩR ≈ Ωφ (ti, T(ti)≈TGUT ≈ 1015GeV
  • Ωφ drives exponential expansion until \color{red}{\varphi \approx \varphi _0 } , \color{red}{T\left( {t_f } \right) \approx e^{ - N} T_{GUT} \approx 10^{ - 28} GeV \approx 10^{ - 15} K} (!)
  • Inflaton then decays, reheats universe