General relativity: intro


General relativity: intro

Why do all masses fall at same rate? All normal forces (e.g. electrical, friction, elastic...) don't produce same accn in all bodies.

\color{red}{ F = m_I a = m_G g \Rightarrow a = g}

Maybe gravity is somehow a fictitious force (?!?!?!?)

\color{red}{ m_I \equiv m_G }

so a = g only if the "inertial mass" is the gravitational mass. Can demonstrate this is true to 1 part in 1012 (Eötvos experiment).


For example:

For example:


General relativity:

Handles frames which are accelerating w.r.t. each other.


General relativity: metrics

Physics should not depend on the frame of reference: e.g. which way is up?

Principle of General Covariance:

physical laws are the same in any frame. (e.g. Newton's are not, since they aren't the same in an accelerating frame). Metric is distance in terms of coords: in Cartesians:
\color{red}{ \Delta s^2 = \Delta x^2 + \Delta y^2 + \Delta z^2 }
In spherical polars:
\color{red}{ \Delta s^2 = \Delta r^2 + r^2 \left( {\Delta \theta ^2 + \sin ^2 \left( \theta \right)\Delta \varphi ^2 } \right)}
Δs² must be the same. Can include time via special rel:
\color{red}{ \Delta \tau ^2 = \Delta t^2 - \frac{1}{{c^2 }}\left( {\Delta x^2 + \Delta y^2 + \Delta z^2 } \right)}
where τ is the proper time. e.g. for a moving body, this could be the interval between creation and decay of a particle, the (invariant) lifetime. This contains (e.g.) time dilation: if the particle is travelling in some frame with vel v = Δr/Δt (t is the time measured in the frame then
\color{red}{ \Delta \tau ^2 = \Delta t^2 - \frac{{v^2 }}{{c^2 }}\Delta t^2 }
so immediately
\color{red}{ \Delta t = \frac{{\Delta \tau }}{{\sqrt {1 - \frac{{v^2 }}{{c^2 }}} }}}
Note that
\color{red}{ \Delta \tau ^2 = \Delta t^2 - \frac{{\Delta r^2 }}{{c^2 }}}
implies that proper time can be real or imaginary: more specifically if we have two events Defines "metric tensor" for us:
in 3-D, the distance between 2 points $ \color{red}{\Delta s^2 }$ cannot depend on the coord. system. Suppose in one system we have $$ \color{red}{ \Delta s^2 = \Delta x^2 + \Delta y^2 + \Delta z^2 } $$
and we write $ \color{red}{x = x\left( {x^1 ,x^2 ,x^3 } \right)}$ etc.. e.g. for polar coords $$ \color{red}{ \begin{array}{l} x = r\sin \left( \varphi \right) \\ y = r\cos \left( \varphi \right) \\ \end{array}} $$ Can now find $$ \color{red}{ \Delta x = \frac{{\partial x}}{{\partial x^1 }}\Delta x^1 + \frac{{\partial x}}{{\partial x^2 }}\Delta x^2 + \frac{{\partial x}}{{\partial x^3 }}\Delta x^3 } $$ etc. Then we can write$$ \color{red}{ \begin{array}{l} \Delta s^2 = \left( {\frac{{\partial x}}{{\partial x^1 }}\Delta x^1 + \frac{{\partial x}}{{\partial x^2 }}\Delta x^2 + \frac{{\partial x}}{{\partial x^3 }}\Delta x^3 } \right)^2 + ..... \\ = \sum\limits_{}^{} {\sum\limits_{}^{} {g_{\mu \nu } \left( {x^1 ,x^2 ,x^3 } \right)\Delta x^\mu \Delta x^\nu } } = g_{\mu \nu } \Delta x^\mu \Delta x^\nu \\ \end{array}} $$

Einstein summation convention: repeated indices are summed over. Note:


Dynamics:

Why bother?

A Body continues at rest or in a state of uniform motion unless acted on by a force.

Uniform motion means in a straight line.

A geodesic in Euclidean space ≡ straight line ≡ shortest path.

Geodesic: shortest time path between 2 points --> straight lines in a flat space


Can either say: