Objectives: by the end of this you will be able to
Understand how fast light travels
Explain the EM spectrum
Explain mirrors
Find what happens to light when it hits a transparent medium
Understand Snell's law and refraction
Draw ray diagrams
Make calculations with simple lenses
Speed of Light
All EM radiation travels with the same speed in vacuum c~2.997x108 ms-1.
Obviously an important quantity to measure.
Originally assumed to be infinite (although Leonardo da Vinci tried to measure it).
First measurement due to Romer, who noticed the predicted time of the eclipses of the satellites of Jupiter was wrong. What difference should he have found
(Rearth = 1.5x108 km,
RJupiter = 7.8x108km)
Problem on earth is measuring very short time intervals:
first good measurements used rotating mirrors (Michelson).
Much more sophisticated methods now.
If the fixed mirror is 30 km from the revolving mirror, how long will it take the light to make the round trip? (c = 3x108 ms-1)
10-4 s
2x10-4 s
2x10-7 s
10-7 s
What would the frequency of rotation of the octagonal (8-sided) mirror need to be so that the next face was in place when the light returned?
5 kHz
2x10-4 Hz
625 Hz
3927 Hz
Electromagnetic Spectrum
We "see" only one octave.
Light is part of the whole electromagnetic spectrum
The "energy' in the above diagram is the energy of the corresponding photon: gets explained later.
Note: we will need
c = λf
repeatedly.
We "see" only one octave.
Why do we see so little of the spectrum? Answer lies in the transparency of the atmosphere
Rule of thumb is that you need an antenna about as big as the wavelength to produce radiation: e.g. to produce radio waves, need a tower, to produce light need an atom. However we can detect most of the ranges.
Reflection
Off a plane surface : Note direction of propagation gets reversed
.
If we have an extended object, this will create an image. To find out where the image appears to be, extend the line of sight
To get the sensation of depth, we need binocular vision
This is based on angle of incidence = angle of reflection
θ₁ = θ₂
This is true even if the surface is curved: e.g. concave mirrors: different bits of the mirror reflect the wave according to the local angle of incidence
The effect in this case is to focus the wave
This is reversible: if we have a source at the centre of a curved mirror, we have a plane wave (well almost) coming out
Convex mirrors cause waves to diverge
Note that these behave as if there is a focus behind the mirror
Refraction
Occurs when a wave passes from one region to another where it moves at a different speed
e.g.
light going from air to glass
light going from air to water .
light going from glass to air
Velocity in medium 1 = v₁ = n₂
Velocity in medium 2 v₂ n₁
n is the refractive index of the medium: for light, the refractive index of the vacuum is defined to be 1, so n > 1
e.g. in crown glass, c ~ 2x108 ms-1 so n = 1.5
Note that the refracted wave is bent since the wavelength is decreased.
This gives rise to Snell's law, when the wave hits the interface at an angle
e.g. light with λ = 520 nm is incident on a piece of crown glass at an angle of 350. What is the refracted wavelength?
λ = 520 nm
λ = 780 nm
λ = 347 nm
What is the refracted angle?
59.40
52.50
23.30
22.50
We have already seen how a single surface refracts. All optical instruments have at least 2 surfaces.
A prism deflects light via two successive refractions
sin(θ₁) = n sin(θ₂)
etc
Total Internal Reflection
Light can go from a dense medium to a less dense one at an "impossible" angle: e.g in crown glass, what would happen to a ray whose angle of incidence was θ = 60o?
e.g. lying on the bottom of a swimming pool looking up what do you see?
A prism can be used to show total internal reflection
In crown glass, what would the angle of incidence need to be such that the outgoing ray was exactly at 900?
60o
90o
42o
48o
Total Internal reflection can occur repeatedly: this is the idea behind fibre optics.
If you want to carry a large amount of signal on one carrier, need a very high frequency (roughly, a voice channel needs 10 kHz, so to carry N voice channels, need 10N kHz.
How many voice channels can you carry on a 1 MHz radio wave?
This is the derivation of the "thin-lens" formula. We can use this to find the relation between the distance to the object, the image and the focal length
The magnification
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M = \frac{{{\rm{image height}}}}{{{\rm{object height}}}} = \frac{{h_i }}{{h_0 }}}